document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301206>Question 301206</A>: <I><SPAN STYLE=\"word-break: break-all;\">  To make 500 liters of a 25% acid solution. How many liters of 30% and18% acid solutions are needed to fill the order?\r<BR>\n" );
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document.write( "(Linear Mixture problem) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215980 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215980\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the quantity of 30 % acid required be x liters\r<BR>\n" );
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document.write( "the 18% acide required will be 500 - x liters\r<BR>\n" );
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document.write( "we need 500 liters 25% acid solution \r<BR>\n" );
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document.write( "0.3x+0.18(500-x) = 0.25 * 500\r<BR>\n" );
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document.write( "0.3x+90-0.18x=125\r<BR>\n" );
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document.write( "0.12x=35\r<BR>\n" );
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document.write( "x= 35/0.12\r<BR>\n" );
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document.write( "291.66 liters of 30% acid is required.\r<BR>\n" );
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document.write( "balance will be 18% acid </SPAN>\n" );
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