document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301114>Question 301114</A>: <I><SPAN STYLE=\"word-break: break-all;\"> My son brought home a few 6th grade algebra problems and I can not remember how to work them.  He does not have his book...so please help if you can.  I'm not even sure what this is called (been a long time for me).  Here's one problem:<BR>\n" );
document.write( "5(2a-1b+3a).  \r<BR>\n" );
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document.write( "Thank you for considering. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215912 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215912\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Just use the distributive law.\r<BR>\n" );
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document.write( "In other words, multiply 5 by every term inside the parentheses.\r<BR>\n" );
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document.write( "5(2a - 1b + 3a) = 10a - 5b + 15a\r<BR>\n" );
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document.write( "We now combine like terms.\r<BR>\n" );
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document.write( "Final Answer: 25a - 5b\r<BR>\n" );
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document.write( "NOTE: There is no reason to place a 1 in front of any variable.\r<BR>\n" );
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document.write( "For example, the middle term in the parentheses given to your son 1b can also be written as b.  Both terms mean the same thing.  </SPAN>\n" );
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