document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=301110>Question 301110</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Algebra II...Word problem:<BR>\n" );
document.write( "     Joe is 10 years older than James. In 8 years, twice Joe's age will will equal 3 times Jame's age. How old is each now?....Nick </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215910 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215910\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let james age be x\r<BR>\n" );
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document.write( "Joe will be x+10\r<BR>\n" );
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document.write( "after 8 years their ages will be\r<BR>\n" );
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document.write( "x+8  & x+10+8\r<BR>\n" );
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document.write( "3(x+8) = 2(x+18)\r<BR>\n" );
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document.write( "3x+24=2x+36\r<BR>\n" );
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document.write( "x=12  jame's age\r<BR>\n" );
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document.write( "joe's age = x+10 = 22 </SPAN>\n" );
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