document.write( "Question 300978: I need help with this word math problem.
\n" ); document.write( "In a collection of nickels, dimes, and quarters, there are twice as many dimes as nickels, and fewer quarters than dimes. If the total value of the coins is $4.50, how many of each type of coin are there?
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Algebra.Com's Answer #215858 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"n\" = number of nickels
\n" ); document.write( "Let \"d\" = number of dimes
\n" ); document.write( "Let \"q\" = number of quarters
\n" ); document.write( "given:
\n" ); document.write( "\"5n+%2B+10d+%2B+25q+=+450\" (in cents)
\n" ); document.write( "\"d+=+2n\"
\n" ); document.write( "\"q+%3C+d\"
\n" ); document.write( "---------
\n" ); document.write( "By substitution:
\n" ); document.write( "\"5n+%2B+10%2A%282n%29+%2B+25q+=+450\"
\n" ); document.write( "\"25n+%2B+25q+=+450\"
\n" ); document.write( "\"n+%2B+q+=+18\"
\n" ); document.write( "\"d%2F2+%2B+q+=+18\"
\n" ); document.write( "I know that \"q%3C18\", since quarters must add up to less than $4.50
\n" ); document.write( "If \"q%3Cd\" then, suppose \"q+=+11\", \"d\" could be \"10\"
\n" ); document.write( "That's $2.75 plus $1.00 = $3.75. If there are twice as many dimes as
\n" ); document.write( "nickels, \"n+=+5\", totaling $.25
\n" ); document.write( "$3.75 + $.25 = $4.00
\n" ); document.write( "My next guess is \"q+=+13\",\"d+=+12\", \"n+=+6\"
\n" ); document.write( "You can go on from here, since you get the idea
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