document.write( "Question 300839: What would be the dimensions if the area of a table is 1650in and the length is 17 inches more than the width? \n" ); document.write( "
Algebra.Com's Answer #215796 by unlockmath(1688)\"\" \"About 
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Hello,
\n" ); document.write( "We can use x to show the width and x+17 to be the length. Now we can set up the following equation: (Note: it should be 1650 Square inches)
\n" ); document.write( "x(x+17)=1650 Rewritten to look:
\n" ); document.write( "x^2+17x-1650=0 Factor this to get:
\n" ); document.write( "(x-33)(x+50)=0 Solve x:
\n" ); document.write( "x=33
\n" ); document.write( "x=-50
\n" ); document.write( "The obvious answer is 33 so the width is 33 inches and length is 50 inches.
\n" ); document.write( "Make sense?
\n" ); document.write( "Check out a book I wrote on the basics of math:
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