document.write( "Question 35472This question is from textbook algebra for college students
\n" ); document.write( ": I need help with this too, Please:\r
\n" ); document.write( "\n" ); document.write( "Find the vertices, the endpoints of the minor axis, and foci of the given ellipse, and sketch it's graph:\r
\n" ); document.write( "\n" ); document.write( "(x+5) squared + 4(y-4) squared = 16
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Algebra.Com's Answer #21579 by rapaljer(4671)\"\" \"About 
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\"%28x%2B5%29%5E2+%2B+4%28y-4%29%5E2+=+16\"\r
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\n" ); document.write( "\n" ); document.write( "Divide both sides of the equation by 16 in order to set it equal to 1, which is standard form for an ellipse.\r
\n" ); document.write( "\n" ); document.write( "\"%28%28x%2B5%29%5E2%29%2F16+%2B+%284%28y-4%29%5E2%29%2F16+=+16%2F16\"\r
\n" ); document.write( "\n" ); document.write( "\"+%28%28x%2B5%29%5E2%29%2F16+%2B+%28%28y-4%29%5E2%29%2F4+=+1\"\r
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\n" ); document.write( "\n" ); document.write( "From this the center of the ellipse will be at (-5,4), the major radius will be in the x direction with \"a%5E2=16\" so a = 4, and the minor radius will be in the y direction with \"b%5E2+=+4\", so b = 2. Since for ellipses, \"a%5E2+=+b%5E2+%2B+c%5E2\", \"16+=+4+%2Bc%5E2\" so c = focal distance which is \"c=+sqrt%2812%29+=+2%2Asqrt%283%29\", applied in the x direction.\r
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\n" ); document.write( "\n" ); document.write( "From that you should be able to sketch the graph and find the vertices, foci, and other information.\r
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\n" ); document.write( "\n" ); document.write( "R^2 at SCC
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