document.write( "Question 300712: a 60% acid solution is to be mixed with a 80% acid solution to produce 20 liters of a 65% acid solution. how many liters of each solution is needed \n" ); document.write( "
Algebra.Com's Answer #215746 by Fombitz(32388)\"\" \"About 
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A - Liters of 60% solution
\n" ); document.write( "B - Liters of 80% solution
\n" ); document.write( "Total volume equation:
\n" ); document.write( "1.\"A%2BB=20\"
\n" ); document.write( ".
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\n" ); document.write( "Total concentration equation:
\n" ); document.write( "\"60A%2B80B=65%2820%29\"
\n" ); document.write( "\"60A%2B80B=1300\"
\n" ); document.write( "2.\"3A%2B4B=65\"
\n" ); document.write( "From eq. 1,
\n" ); document.write( "\"A=20-B\"
\n" ); document.write( "Substitute into eq. 2,
\n" ); document.write( "\"3%2820-B%29%2B4B=65\"
\n" ); document.write( "\"60-3B%2B4B=65\"
\n" ); document.write( "\"B=5\"
\n" ); document.write( "Then from eq. 1,
\n" ); document.write( "\"A=20-B\"
\n" ); document.write( "\"A=20-5\"
\n" ); document.write( "\"A=15\"
\n" ); document.write( "Use 15 liters of 60% solution and 5 liters of 80% solution
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