document.write( "Question 300757: 2. Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers).
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document.write( "a. If you have a body temperature of 99.00 °F, what is your percentile score?
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document.write( "b. Convert 99.00 °F to a standard score (or a z-score).
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document.write( "c. Is a body temperature of 99.00 °F unusual? Why or why not?
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document.write( "d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 °F or lower?
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document.write( "e. A person’s body temperature is found to be 101.00 °F. Is the result unusual? Why or why not? What should you conclude?
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document.write( "f. What body temperature is the 95th percentile?
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document.write( "g. What body temperature is the 5th percentile?
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document.write( "h. Bellevue Hospital in New York City uses 100.6 °F as the lowest temperature considered to indicate a fever. What percentage of normal and healthy adults would be considered to have a fever? Does this percentage suggest that a cutoff of 100.6 °F is appropriate?\r
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Algebra.Com's Answer #215733 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! 2. Assume the body temperatures of healthy adults are normally distributed with a mean of 98.20 °F and a standard deviation of 0.62 °F (based on data from the University of Maryland researchers). \n" ); document.write( "a. If you have a body temperature of 99.00 °F, what is your percentile score? \n" ); document.write( "Find the z-score for 99. \n" ); document.write( "Find the percent of population with a z-score that is less than \n" ); document.write( "the z-score for 99. \n" ); document.write( "The is the percentile score of 99 \n" ); document.write( "------------------------------------------ \n" ); document.write( "b. Convert 99.00 °F to a standard score (or a z-score). \n" ); document.write( "You've had to do that in the \"a\" problem. \n" ); document.write( "-------------------------------------------------- \n" ); document.write( "c. Is a body temperature of 99.00 °F unusual? Why or why not? \n" ); document.write( "If its z-score is less than -2 or more than +2 it is considered \n" ); document.write( "to be \"unusual\". \n" ); document.write( "----------------------------- \n" ); document.write( "d. Fifty adults are randomly selected. What is the likelihood that the mean of their body temperatures is 97.98 °F or lower? \n" ); document.write( "Find the z-score of 97.98 using mean = 98.2 and std = 0.62/sqrt(50) \n" ); document.write( "----------------------------- \n" ); document.write( "e. A person’s body temperature is found to be 101.00 °F. Is the result unusual? Why or why not? What should you conclude? \n" ); document.write( "Find the z-score of 101 and make your conclusion. \n" ); document.write( "------ \n" ); document.write( "f. What body temperature is the 95th percentile? \n" ); document.write( "Find the z-score with a left tail of 0.95. \n" ); document.write( "Convert to a temperature score using temp = z*s+u \n" ); document.write( "----------------------------------- \n" ); document.write( "g. What body temperature is the 5th percentile? \n" ); document.write( "Findt the z-score with a left tail of 5%. \n" ); document.write( "Convert to a temperature score using temp = z*s+u \n" ); document.write( "------------------------------------- \n" ); document.write( "h. Bellevue Hospital in New York City uses 100.6 °F as the lowest temperature considered to indicate a fever. What percentage of normal and healthy adults would be considered to have a fever? \n" ); document.write( "Find the z-score of 100.6. \n" ); document.write( "Find the percent population above that z-score.\r \n" ); document.write( "\n" ); document.write( "---------------------------- \n" ); document.write( "Does this percentage suggest that a cutoff of 100.6 °F is appropriate? \n" ); document.write( "Make your judgement. \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |