document.write( "Question 300704: Tom's present age is twice Sue's present age. Two years ago, Tom was three times as old as Sue was then. Find their present ages. \n" ); document.write( "
Algebra.Com's Answer #215714 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let sue's age be x\r \n" ); document.write( "\n" ); document.write( "tom's age will be 2x\r \n" ); document.write( "\n" ); document.write( "2 years ago sue was x-2 years \n" ); document.write( "tom was 2x-2 years\r \n" ); document.write( "\n" ); document.write( "At that time tom was thrice as old as sue\r \n" ); document.write( "\n" ); document.write( "3(x-2) = 2x-2\r \n" ); document.write( "\n" ); document.write( "3x-6 = 2x-2\r \n" ); document.write( "\n" ); document.write( "x= 6-2\r \n" ); document.write( "\n" ); document.write( "x=4 which is sue's age\r \n" ); document.write( "\n" ); document.write( "tom is 2x = 8 years\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |