document.write( "Question 300679: Judy is 12 years older than Joan. In 7 years, the sum of thier ages will be 42. How old is each now? \n" ); document.write( "
Algebra.Com's Answer #215707 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
Judy is 12 years older than Joan. In 7 years, the sum of thier ages will be 42. How old is each now?\r
\n" ); document.write( "\n" ); document.write( "let joan's age be x\r
\n" ); document.write( "\n" ); document.write( "judy's age will be x+12\r
\n" ); document.write( "\n" ); document.write( "after 7 years their ages will be x+7 & (x+12) years\r
\n" ); document.write( "\n" ); document.write( "x+7 + ( x+12 )+7 = 42\r
\n" ); document.write( "\n" ); document.write( "x+7 + x+12 +7= 42\r
\n" ); document.write( "\n" ); document.write( "2x+26=42\r
\n" ); document.write( "\n" ); document.write( "2x=42-26\r
\n" ); document.write( "\n" ); document.write( "2x=12\r
\n" ); document.write( "\n" ); document.write( "x=6 which is joan\"s age\r
\n" ); document.write( "\n" ); document.write( "Judy's age = 12+6 =18 years\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );