document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=4632>Question 4632</A>: <I><SPAN STYLE=\"word-break: break-all;\"> i^91=?<BR>\n" );
document.write( "This question was asked previously (question 3340), and the given soluttion was to find where i^91 came in the cycle of i. However I learned another way to do it, and I was wondering if it is correct.<BR>\n" );
document.write( "Take the given question i^91:<BR>\n" );
document.write( "i^91 = i^90 + 1<BR>\n" );
document.write( "     = i^90 * i^1<BR>\n" );
document.write( "     = (i^2)^45*i^1<BR>\n" );
document.write( "     = -1^45 * i^1<BR>\n" );
document.write( "     = -1 * i<BR>\n" );
document.write( "     = -i<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #2157 by </B><A HREF=/tutors/aboutme.mpl?userid=longjonsilver><B>longjonsilver(2297)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=longjonsilver><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=longjonsilver><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=2157\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> this line: i^91 = i^90 + 1 is not needed (and is in fact incorrect). Take it out then the rest is a perfect answer, yes. Well done.\r<BR>\n" );
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document.write( "Jon.\r<BR>\n" );
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document.write( " </SPAN>\n" );
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