document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=300684>Question 300684</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the area of a right triangular rug is 12 squar feet. the length of the rug is 2 feet more then the width of the rug. what is the width od the right triangular rug?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215695 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215695\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the width of the rug be x feet\r<BR>\n" );
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document.write( "the length will be x+2\r<BR>\n" );
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document.write( "Area of triangle = 1/2 * side1 * side2 since it is right angled\r<BR>\n" );
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document.write( "12= 1/2 x(x+2)\r<BR>\n" );
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document.write( "24 = x^2 +2x\r<BR>\n" );
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document.write( "x^2 +2x-24 = 0\r<BR>\n" );
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document.write( "x^2+6x-4x-24 =0\r<BR>\n" );
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document.write( "x(x+6)-4(x+6)=0\r<BR>\n" );
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document.write( "(x+6)(x-4) =0\r<BR>\n" );
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document.write( "x=-6 or x=4\r<BR>\n" );
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document.write( "4feet is the width of the rug\r<BR>\n" );
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