document.write( "Question 35317: Adding rational #
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document.write( "Cant figure this problem out..Any help will be appreciated.\r
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document.write( "5 1
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document.write( "_____ + _______
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document.write( "7x+35 42x+126\r
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document.write( "I tried factoring both Denominator
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document.write( "7(x+5) 42(x+3)
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document.write( "then 7(42)=294(x+5)(x+3)\r
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document.write( "I am lost after that \n" );
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Algebra.Com's Answer #21569 by rapaljer(4671) You can put this solution on YOUR website! \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your problem was that you did not find the Lowest Common Denominator. Notice that 7 divides evenly into 42, so the LCD = \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, multiply the first fraction by 6(x+3) and the second fraction by (x+5):\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Now, the LCD is 42(x+3)(x+5), and that becomes the denominator of the fraction. The numerator of the fraction becomes the sum of the numerators. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "NOW DON'T DIVIDE ANY OF THESE OUT!! They look like factors, but they are NOT factors!! Multiply out the numerators. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "R^2 at SCC\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |