document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=300606>Question 300606</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A landscaper designed a garden such that a grass path of uniform width surrounds a rectangular fountain. The fountain is 60m long & 40m wide, & the area of the graa path is 616m^2. Determine the width of the grass path  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215663 by </B><A HREF=/tutors/aboutme.mpl?userid=alanc><B>alanc(27)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=alanc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=alanc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215663\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Miscellaneous_Word_Problems/300606 (2010-05-04 19:55:27): A landscaper designed a garden such that a grass path of uniform width surrounds a rectangular fountain. The fountain is 60m long & 40m wide, & the area of the graa path is 616m^2. Determine the width of the grass path \r<BR>\n" );
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document.write( " 60 by 40\r<BR>\n" );
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document.write( "616 square meters\r<BR>\n" );
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document.write( "x * y = A;     A - 60*40 = 616\r<BR>\n" );
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document.write( "x = 60 + 2l<BR>\n" );
document.write( "y = 40 + 2l\r<BR>\n" );
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document.write( "Since the width of the grass path is constant, I'll name it l and it augments the original fountain length and width by 2l.\r<BR>\n" );
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document.write( "(60 + 2l)*(40 + 2l) = 60*40 + 616\r<BR>\n" );
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document.write( "(fountain area plus grass path area should equal the new length * new width).\r<BR>\n" );
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document.write( "60*40 + 616 = 2400 + 616 = 3016.\r<BR>\n" );
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document.write( "2400 + 4*l*l + 120*l + 80*l = 2400 + 4*l*l + 200*l = 3016\r<BR>\n" );
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document.write( "we have   4*l*l + 200*l -616 = 0\r<BR>\n" );
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document.write( "l = -200/(2*4)  +  [sqrt(200*200 - 4*4*(-616))] /(2*4)\r<BR>\n" );
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document.write( "l = -25  + sqrt(49856) / 8\r<BR>\n" );
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document.write( "l = -25 +  223.28457179124580079903972119481 / 8\r<BR>\n" );
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document.write( "l = 27.910571473905725099879965149351 - 25\r<BR>\n" );
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document.write( "l = 2.9105 m\r<BR>\n" );
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