document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=300542>Question 300542</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36. The ratio of the lengths of the sides is 2 : 7. What are the lengths of the sides?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215651 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215651\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The perimeter of a rectangle is 36. The ratio of the lengths of the sides is 2 : 7. What are the lengths of the sides?\r<BR>\n" );
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document.write( "Let L be the length and W the width of the rectangle. We know that:\r<BR>\n" );
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document.write( "1.) W/L = 2/7 or<BR>\n" );
document.write( "W = (2/7)*L\r<BR>\n" );
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document.write( "2.) 36 = 2*W + 2*L\r<BR>\n" );
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document.write( "Substituting (2/7)*L for W in equation 2.) we have:\r<BR>\n" );
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document.write( "36 = 2*(2/7)*L + 2*L<BR>\n" );
document.write( "36 = (4/7)*L + (14/7)*L<BR>\n" );
document.write( "36 = (18/7)*L\r<BR>\n" );
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document.write( "Multiply both sides by 7/18:\r<BR>\n" );
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document.write( "36*(7/18) = 1*L<BR>\n" );
document.write( "14 = L\r<BR>\n" );
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document.write( "Calculate W = (2/7)*L\r<BR>\n" );
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document.write( "W = (2/7)*14<BR>\n" );
document.write( "W = 4 </SPAN>\n" );
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