document.write( "Question 300479: How many liters of pure acid must be mixed with 14 liters of 20% acid solution to get a 30% mixture? \n" ); document.write( "

Algebra.Com's Answer #215623 by Fombitz(32388) $\"\"$ $\"About$

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Let L be the liters of pure acid.
\n" ); document.write( " $\"100%2AL%2B20%2814%29=30%28L%2B14%29\"$
\n" ); document.write( " $\"100L%2B280=30L%2B420\"$
\n" ); document.write( " $\"70L=140\"$
\n" ); document.write( " $\"L=2\"$
\n" ); document.write( "2 liters of pure acid added to 14 liters of 20% solution will yield 16 liters of 30% solution. \n" ); document.write( "

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