document.write( "Question 300399: When the digits of a two-digit number are reversed,the new number is 9 more than the original number,and the sum of digits of the original number is 11.What is the original?
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document.write( "I really need help with setting this up and how to check.
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document.write( " Please and Thank you! \n" );
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Algebra.Com's Answer #215582 by JBarnum(2146) You can put this solution on YOUR website! original number: (ab)=10a+b \n" ); document.write( "new number: (ba)=10b+a \n" ); document.write( "a+b=11 \n" ); document.write( "(ba)=9+10a+b\r \n" ); document.write( "\n" ); document.write( "hmm this is harder to explain then i thought. \n" ); document.write( "[for example take number 45=(10(4)+5) if reversed its 54=(10(5)+4). 4+5=9 sum of digits of original number 45, (10(4)+5)+9=54 added 9 to the original 45 to get the new number 54.] \n" ); document.write( "same type of thing for this problem \n" ); document.write( "a and be have to be single whole numbers that add to get 11 \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "________ \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "________ \n" ); document.write( "check \n" ); document.write( "(ab)=10a+b \n" ); document.write( "(ab)=10(5)+(6) \n" ); document.write( "(ab)=(56) \n" ); document.write( "__ \n" ); document.write( "(ba)=10b+a \n" ); document.write( "(ba)=10(6)+(5) \n" ); document.write( "(ba)=(65) \n" ); document.write( "__ \n" ); document.write( "(ba)=9+(ab) \n" ); document.write( "(65)=9+(56) \n" ); document.write( "(65)=(65) \n" ); document.write( "CORRECT\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |