document.write( "Question 300399: When the digits of a two-digit number are reversed,the new number is 9 more than the original number,and the sum of digits of the original number is 11.What is the original?
\n" ); document.write( "I really need help with setting this up and how to check.
\n" ); document.write( " Please and Thank you!
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Algebra.Com's Answer #215571 by Fombitz(32388)\"\" \"About 
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The original number is AB where the actual value is 10*A+B.
\n" ); document.write( "The reversed digits number is BA and its actual value is 10*B+A.
\n" ); document.write( "Nw turn the words into equations.
\n" ); document.write( "\"sum of digits is 11\"
\n" ); document.write( "1.\"A%2BB=11\"
\n" ); document.write( "\"the digits of a two-digit number are reversed,the new number is 9 more than the original number\"
\n" ); document.write( "\"10%2AB%2BA=9%2B10%2AA%2BB\"
\n" ); document.write( "\"-9A%2B9B=9\"
\n" ); document.write( "2.\"-A%2BB=1\"
\n" ); document.write( "Now you have two equations in A and B.
\n" ); document.write( "Add them together to eliminate A and solve for B. THen go back and solve for A.
\n" ); document.write( "To check your answer, run through the two requirements and make sure the digits meet them.
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