document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=300351>Question 300351</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A house purchased last year for $80,000 is now worth $96,000. Assuming that the value of the house continues to appreciate (increase) at the same rate each year, find the value 2 years from now?\r<BR>\n" );
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document.write( "THANK YOU! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215556 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215556\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> R=96000/80000=1.2<BR>\n" );
document.write( "Next year, it would be worth 96,000(1.2)=$115,200.<BR>\n" );
document.write( "Then the year after,would be 115200(1.2)=$138,240. </SPAN>\n" );
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