document.write( "Question 300301: Rectangle A is 4.5 times as long as it is wide. Rectangle B is 8 inches wider and 20 inches shorter. The rectangles have the same area. What is the width of Rectangle B? \n" ); document.write( "
Algebra.Com's Answer #215530 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! Rectangle A is 4.5 times as long as it is wide. Rectangle B is 8 inches wider and 20 inches shorter. The rectangles have the same area. What is the width of Rectangle B? \n" ); document.write( ". \n" ); document.write( "Rect A: \n" ); document.write( "Let x = width \n" ); document.write( "then \n" ); document.write( "4.5x = length \n" ); document.write( ". \n" ); document.write( "Rect B: \n" ); document.write( "x+8 = width \n" ); document.write( "4.5x-20 = length \n" ); document.write( ". \n" ); document.write( "Since area is the same: \n" ); document.write( "x(4.5x) = (x+8)(4.5x-20) \n" ); document.write( "4.5x^2 = 4.5x^2-20x+36x-160 \n" ); document.write( "4.5x^2 = 4.5x^2+16x-160 \n" ); document.write( "0 = 16x-160 \n" ); document.write( "160 = 16x \n" ); document.write( "10 inches = x \n" ); document.write( ". \n" ); document.write( "Width of rectangle B: \n" ); document.write( "x+8 = 10+8 = 18 inches \n" ); document.write( " \n" ); document.write( " |