document.write( "Question 300301: Rectangle A is 4.5 times as long as it is wide. Rectangle B is 8 inches wider and 20 inches shorter. The rectangles have the same area. What is the width of Rectangle B? \n" ); document.write( "
Algebra.Com's Answer #215530 by nerdybill(7384)\"\" \"About 
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Rectangle A is 4.5 times as long as it is wide. Rectangle B is 8 inches wider and 20 inches shorter. The rectangles have the same area. What is the width of Rectangle B?
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\n" ); document.write( "Rect A:
\n" ); document.write( "Let x = width
\n" ); document.write( "then
\n" ); document.write( "4.5x = length
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\n" ); document.write( "Rect B:
\n" ); document.write( "x+8 = width
\n" ); document.write( "4.5x-20 = length
\n" ); document.write( ".
\n" ); document.write( "Since area is the same:
\n" ); document.write( "x(4.5x) = (x+8)(4.5x-20)
\n" ); document.write( "4.5x^2 = 4.5x^2-20x+36x-160
\n" ); document.write( "4.5x^2 = 4.5x^2+16x-160
\n" ); document.write( "0 = 16x-160
\n" ); document.write( "160 = 16x
\n" ); document.write( "10 inches = x
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\n" ); document.write( "Width of rectangle B:
\n" ); document.write( "x+8 = 10+8 = 18 inches
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