document.write( "Question 300316: Use the formula N = Iekt, where N is the number of items in terms of the initial population I, at time t, and k is the growth constant equal to the percent of growth per unit of time. There are currently 63 million cars in a certain country, decreasing by 6.9% annually. How many years will it take for this country to have 33 million cars? Round to the nearest year. \n" ); document.write( "
Algebra.Com's Answer #215526 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Use the formula N = Iekt, where N is the number of items in terms of the initial population I, at time t, and k is the growth constant equal to the percent of growth per unit of time. There are currently 63 million cars in a certain country, decreasing by 6.9% annually. How many years will it take for this country to have 33 million cars? Round to the nearest year. \n" ); document.write( "--------------------------------- \n" ); document.write( "N = I*e^(kt) \n" ); document.write( "--- \n" ); document.write( "Solve for \"t\" if I = 63 million, N = 33x10^6 and k = -0.069 \n" ); document.write( "----------- \n" ); document.write( "33 = 63*e^(-0.069t) \n" ); document.write( "--- \n" ); document.write( "e^(-0.069t) = 11/21 \n" ); document.write( "--- \n" ); document.write( "Take the natural log of both sides to get: \n" ); document.write( "-0.069t = ln(11/21) \n" ); document.write( "t = 9.37 years \n" ); document.write( "======================= \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================= \n" ); document.write( " |