document.write( "Question 299963: If bill rides his bike 3 miles to Fred's house and then walks with Fred the remaining 1 mile to school, it will take him 30 minutes. But if he rides the entire distance, it will take him only 20 minutes. what is his walking and biking speed?
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Algebra.Com's Answer #215417 by ankor@dixie-net.com(22740)\"\" \"About 
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If bill rides his bike 3 miles to Fred's house and then walks with Fred the
\n" ); document.write( " remaining 1 mile to school, it will take him 30 minutes.
\n" ); document.write( "But if he rides the entire distance, it will take him only 20 minutes.
\n" ); document.write( " what is his walking and biking speed?
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\n" ); document.write( "let b = biking speed
\n" ); document.write( "let w = walking speed
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\n" ); document.write( "Write two time equations; time = dist/speed:
\n" ); document.write( "ride and walk equation
\n" ); document.write( "\"3%2Fb\" + \"1%2Fw\" = \"1%2F2\"
\n" ); document.write( "and
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\n" ); document.write( "\"4%2Fb\" = \"1%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "b = 4*3
\n" ); document.write( "b = 12 mph is the biking speed
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\n" ); document.write( "Find the walking speed using the 1st equation
\n" ); document.write( "\"3%2F12\" + \"1%2Fw\" = \"1%2F2\"
\n" ); document.write( "multiply by 12w, results:
\n" ); document.write( "3w + 12 = 6w
\n" ); document.write( "12 = 6w - 3w
\n" ); document.write( "3w = 12
\n" ); document.write( "w = 4 mph is the walking speed
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\n" ); document.write( "Check solution using the 1st equation
\n" ); document.write( "\"3%2F12\" + \"1%2F4\" =
\n" ); document.write( "\"1%2F4\" + \"1%2F4\" = \"1%2F2\"
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