document.write( "Question 300031: The bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 miles per hour faster than the other, what was the speed of the bicyclist? \n" ); document.write( "
Algebra.Com's Answer #215407 by checkley77(12844)\"\" \"About 
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D=RT
\n" ); document.write( "300=(R+R+20)*6
\n" ); document.write( "300=(2R+20)*6
\n" ); document.write( "300=12R+120
\n" ); document.write( "12R=300-120
\n" ); document.write( "12R=180
\n" ); document.write( "R=180/12
\n" ); document.write( "R=15 MPH IS THE SPEED OF THE SLOWER RIDER.
\n" ); document.write( "15+20=35 MPH. IS THE SPEED OF THE FASTER RIDER.
\n" ); document.write( "PROOF:
\n" ); document.write( "300=(15+35)*6
\n" ); document.write( "300=50*6
\n" ); document.write( "300=300
\n" ); document.write( "
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