document.write( "Question 300031: The bicyclists were 300 miles apart at 3 p.m. and were headed toward each other. If they met at 9 p.m. and one was traveling 20 miles per hour faster than the other, what was the speed of the bicyclist? \n" ); document.write( "
Algebra.Com's Answer #215407 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "300=(R+R+20)*6 \n" ); document.write( "300=(2R+20)*6 \n" ); document.write( "300=12R+120 \n" ); document.write( "12R=300-120 \n" ); document.write( "12R=180 \n" ); document.write( "R=180/12 \n" ); document.write( "R=15 MPH IS THE SPEED OF THE SLOWER RIDER. \n" ); document.write( "15+20=35 MPH. IS THE SPEED OF THE FASTER RIDER. \n" ); document.write( "PROOF: \n" ); document.write( "300=(15+35)*6 \n" ); document.write( "300=50*6 \n" ); document.write( "300=300 \n" ); document.write( " |