document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299932>Question 299932</A>: <I><SPAN STYLE=\"word-break: break-all;\"> There is a Circle with the Diameter as 5.  This is inside of a square which has a base of 17.  How Do You Find the Area?  Please show all work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215399 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215399\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the area of what?  The square?  The circle? The shaded region?  If you seek the area of the shaded region, which region?\r<BR>\n" );
document.write( "\n" );
document.write( "If you simply want the area of the circle, then we need to know certain facts from the given information.\r<BR>\n" );
document.write( "\n" );
document.write( "If the diameter is 5, then the radius is (1/2) times diameter or in this case<BR>\n" );
document.write( "(5/2).\r<BR>\n" );
document.write( "\n" );
document.write( "We now use the area of a circle formula, which is A = pi*(r^2), where pi = 3.14<BR>\n" );
document.write( "and r = (5/2).\r<BR>\n" );
document.write( "\n" );
document.write( "A = (3.14)(5/2)^2\r<BR>\n" );
document.write( "\n" );
document.write( "A = 19.625\r<BR>\n" );
document.write( "\n" );
document.write( "Is this what you are looking for?\r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );