document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=300020>Question 300020</A>: <I><SPAN STYLE=\"word-break: break-all;\"> factor out common factor\r<BR>\n" );
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document.write( "15x^4y+5x^2y^3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215393 by </B><A HREF=/tutors/aboutme.mpl?userid=nyc_function><B>nyc_function(2741)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nyc_function><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nyc_function><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215393\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The common factor is a number or term, in this case, that evenly divides both terms in your expression.\r<BR>\n" );
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document.write( "If I am going to divided 15x^4y and 5x^2y^3 by a factor that will produce a number or term with no remainder, what factor can that be?\r<BR>\n" );
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document.write( "It would have to 5x^2y.  This term factors evenly into 15x^4y and 5x^2y^3.\r<BR>\n" );
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document.write( "If you don't believe me, try it out.\r<BR>\n" );
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