document.write( "Question 299857: i have a triangle with sides 8,7, 10 . i must find the measure of the angle opposite of side 10. please help if possible. thank you \n" ); document.write( "

Algebra.Com's Answer #215381 by ankor@dixie-net.com(22740) $\"\"$ $\"About$

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: i have a triangle with sides 8,7, 10 . i must find the measure of the angle opposite of side 10. please help if possible. thank you
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\n" ); document.write( "We can use the law of cosines here
\n" ); document.write( "Assign the sides as follows
\n" ); document.write( "a=8, b=7, c=10, then C = angle opposite 10
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\n" ); document.write( "a^2 + b^2 - 2bc*cos(C) = c^2
\n" ); document.write( "using the above values
\n" ); document.write( "8^2 + 7^2 - 2(8*7) * cos(C) = 10^2
\n" ); document.write( "64 + 49 - 2(56)*cos(C) = 100
\n" ); document.write( "113 - 112*cos(C) = 100
\n" ); document.write( "-112*cos(C) = 100 - 113
\n" ); document.write( "cos(C) = $\"-13%2F-112\"$
\n" ); document.write( "cos(C) = +.11607
\n" ); document.write( "C = 83.33 degrees
\n" ); document.write( ":
\n" ); document.write( "That's the procedure, but check my math
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