document.write( "Question 299694: A rectangular chart is 1 9⁄12 times as long as it is wide. If it were 10 centimeter longer and 1 centimeter wider, its area would be 57 square centimeters larger. How long is the chart? \n" ); document.write( "
Algebra.Com's Answer #215309 by ankor@dixie-net.com(22740)\"\" \"About 
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A rectangular chart is 1 9⁄12 times as long as it is wide.
\n" ); document.write( " If it were 10 centimeter longer and 1 centimeter wider, its area would be 57
\n" ); document.write( "square centimeters larger. How long is the chart?
\n" ); document.write( ":
\n" ); document.write( "Convert 1\"9%2F12\" to 1.75
\n" ); document.write( ":
\n" ); document.write( "L = 1.75W
\n" ); document.write( "Find the original area
\n" ); document.write( "A = L*W
\n" ); document.write( "A1 = 1.75W^2
\n" ); document.write( ":
\n" ); document.write( "Find the new area:
\n" ); document.write( "A2 = (1.75W+10) * (W+1)
\n" ); document.write( "FOIL
\n" ); document.write( "A2 = 1.75W^2 + 1.75W + 10W + 10
\n" ); document.write( "A2 = 1.75W^2 + 11.75W + 10
\n" ); document.write( ":
\n" ); document.write( "New area - original area = 57 sq/cm
\n" ); document.write( "1.75W^2 + 11.75W + 10 - 1.75W^2 = 57
\n" ); document.write( "11.75W = 57 - 10
\n" ); document.write( "11.75W = \"47%2F11.75\"
\n" ); document.write( "W = 4 cm is the original Width
\n" ); document.write( ":
\n" ); document.write( "L = 1.75 * 4
\n" ); document.write( "L = 7 cm is the original length
\n" ); document.write( ":
\n" ); document.write( "Check this
\n" ); document.write( "new dimensions: 17 by 5
\n" ); document.write( "(17*5) - (7*4) =
\n" ); document.write( "85 - 28 = 57; confirms our answers
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