document.write( "Question 299694: A rectangular chart is 1 9⁄12 times as long as it is wide. If it were 10 centimeter longer and 1 centimeter wider, its area would be 57 square centimeters larger. How long is the chart? \n" ); document.write( "
Algebra.Com's Answer #215309 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A rectangular chart is 1 9⁄12 times as long as it is wide. \n" ); document.write( " If it were 10 centimeter longer and 1 centimeter wider, its area would be 57 \n" ); document.write( "square centimeters larger. How long is the chart? \n" ); document.write( ": \n" ); document.write( "Convert 1 \n" ); document.write( ": \n" ); document.write( "L = 1.75W \n" ); document.write( "Find the original area \n" ); document.write( "A = L*W \n" ); document.write( "A1 = 1.75W^2 \n" ); document.write( ": \n" ); document.write( "Find the new area: \n" ); document.write( "A2 = (1.75W+10) * (W+1) \n" ); document.write( "FOIL \n" ); document.write( "A2 = 1.75W^2 + 1.75W + 10W + 10 \n" ); document.write( "A2 = 1.75W^2 + 11.75W + 10 \n" ); document.write( ": \n" ); document.write( "New area - original area = 57 sq/cm \n" ); document.write( "1.75W^2 + 11.75W + 10 - 1.75W^2 = 57 \n" ); document.write( "11.75W = 57 - 10 \n" ); document.write( "11.75W = \n" ); document.write( "W = 4 cm is the original Width \n" ); document.write( ": \n" ); document.write( "L = 1.75 * 4 \n" ); document.write( "L = 7 cm is the original length \n" ); document.write( ": \n" ); document.write( "Check this \n" ); document.write( "new dimensions: 17 by 5 \n" ); document.write( "(17*5) - (7*4) = \n" ); document.write( "85 - 28 = 57; confirms our answers \n" ); document.write( " \n" ); document.write( " |