document.write( "Question 299771: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.\r
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document.write( "The product of two consecutive positive odd integers is one less than twice their sum. Find the integers. show work I am really confused with this please help me!!!\r
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document.write( "thanks
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Algebra.Com's Answer #215292 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The product of two consecutive positive odd integers is one less than twice their sum. \n" ); document.write( "--- \n" ); document.write( "Note: Odd integers are always one less than \n" ); document.write( "or one more than an even integer. \n" ); document.write( "Even integers are always a multiple of 2. \n" ); document.write( "------------------------------------------------- \n" ); document.write( "Your Problem: \n" ); document.write( "1st: 2x-1 \n" ); document.write( "2nd: 2x+1 \n" ); document.write( "--- \n" ); document.write( "Equation: \n" ); document.write( "product = 2(sum) - 1 \n" ); document.write( "(2x-1)(2x+1) = 2(2x-1+2x+1)-1 \n" ); document.write( "4x^2-1 = 2(4x) -1 \n" ); document.write( "4x^2 = 8x \n" ); document.write( "4x(x-2) = 0 \n" ); document.write( "x = 0 or x = 2 \n" ); document.write( "---- \n" ); document.write( "If x = 0: \n" ); document.write( "1st = 2x-1 = -1 \n" ); document.write( "2nd = 2x+1 = 1 \n" ); document.write( "Since you want \"positive odd integers\", x = 0 is not a solution. \n" ); document.write( "------------------ \n" ); document.write( "If x = 2: \n" ); document.write( "1st = 2x-1 = 3 \n" ); document.write( "2nd = 2x+1 = 5 \n" ); document.write( "This pair is the only solution.\r \n" ); document.write( "\n" ); document.write( "=================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |