document.write( "Question 299771: Solve using the five-step problem-solving process. Show all steps necessary to arrive at your solution.\r
\n" ); document.write( "\n" ); document.write( "The product of two consecutive positive odd integers is one less than twice their sum. Find the integers. show work I am really confused with this please help me!!!\r
\n" ); document.write( "\n" ); document.write( "thanks
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #215292 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The product of two consecutive positive odd integers is one less than twice their sum.
\n" ); document.write( "---
\n" ); document.write( "Note: Odd integers are always one less than
\n" ); document.write( "or one more than an even integer.
\n" ); document.write( "Even integers are always a multiple of 2.
\n" ); document.write( "-------------------------------------------------
\n" ); document.write( "Your Problem:
\n" ); document.write( "1st: 2x-1
\n" ); document.write( "2nd: 2x+1
\n" ); document.write( "---
\n" ); document.write( "Equation:
\n" ); document.write( "product = 2(sum) - 1
\n" ); document.write( "(2x-1)(2x+1) = 2(2x-1+2x+1)-1
\n" ); document.write( "4x^2-1 = 2(4x) -1
\n" ); document.write( "4x^2 = 8x
\n" ); document.write( "4x(x-2) = 0
\n" ); document.write( "x = 0 or x = 2
\n" ); document.write( "----
\n" ); document.write( "If x = 0:
\n" ); document.write( "1st = 2x-1 = -1
\n" ); document.write( "2nd = 2x+1 = 1
\n" ); document.write( "Since you want \"positive odd integers\", x = 0 is not a solution.
\n" ); document.write( "------------------
\n" ); document.write( "If x = 2:
\n" ); document.write( "1st = 2x-1 = 3
\n" ); document.write( "2nd = 2x+1 = 5
\n" ); document.write( "This pair is the only solution.\r
\n" ); document.write( "\n" ); document.write( "===================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );