document.write( "Question 299705: Pls. help me solve these problem:
\n" ); document.write( "A grassy plot 25m by 30m is surrounded by a walk of uniform width. If the area of the walk is 300sq. m., how wide is it?
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Algebra.Com's Answer #215264 by nerdybill(7384)\"\" \"About 
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A grassy plot 25m by 30m is surrounded by a walk of uniform width. If the area of the walk is 300sq. m., how wide is it?
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\n" ); document.write( "\"area of grassy plot AND walk\" minus \"area of grassy plot\" equals 300
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\n" ); document.write( "Let x = width of walk
\n" ); document.write( "then
\n" ); document.write( "(25+2x)(30+2x) - (25)(30) = 300
\n" ); document.write( "(25+2x)(30+2x) - (25)(30) = 300
\n" ); document.write( "750+50x+60x+4x^2 - 750 = 300
\n" ); document.write( "50x+60x+4x^2 = 300
\n" ); document.write( "4x^2+110x = 300
\n" ); document.write( "4x^2+110x-300 = 0
\n" ); document.write( "2x^2+55x-150 = 0
\n" ); document.write( "2x^2+60x-5x-150 = 0
\n" ); document.write( "(2x^2+60x)-(5x+150) = 0
\n" ); document.write( "2x(x+30)-5(x+30) = 0
\n" ); document.write( "(2x-5)(x+30) = 0
\n" ); document.write( "x = {5/2, -30}
\n" ); document.write( "We can throw out the negative answer leaving:
\n" ); document.write( "x = 5/2 = 2.5 meters
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