document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299674>Question 299674</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Heather reeived grades of 80, 75, and 86 on three algebra tests.  What must her grade be on the next test if her average for the four tests is to be at least 82?  How do I solve this problem? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215253 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215253\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">     Heather reeived grades of 80, 75, and 86 on three algebra tests. What must her grade be on the next test if her average for the four tests is to be at least 82? How do I solve this problem?<BR>\n" );
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document.write( "Let x = score on fourth test<BR>\n" );
document.write( "then<BR>\n" );
document.write( "(80+75+86+x)/4 = 82<BR>\n" );
document.write( "(241+x)/4 = 82<BR>\n" );
document.write( "241+x = 82*4<BR>\n" );
document.write( "241+x = 328<BR>\n" );
document.write( "x = 87<BR>\n" );
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document.write( "That is Heather's score must be >= 87<BR>\n" );
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