document.write( "Question 299667: need help with this word problem:\r
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document.write( "shelly can cut a lawn with a riding mower in 5 hours less time than it takes William to cut a lawn with a push mower, if they can cut the lawn in 2 hours working together find how long to the nearest tenth of an hour it takes for William to cut the lawn alone. \n" );
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Algebra.Com's Answer #215252 by nerdybill(7384)![]() ![]() You can put this solution on YOUR website! shelly can cut a lawn with a riding mower in 5 hours less time than it takes William to cut a lawn with a push mower, if they can cut the lawn in 2 hours working together find how long to the nearest tenth of an hour it takes for William to cut the lawn alone. \n" ); document.write( ". \n" ); document.write( "Let w = time it takes for William to cut lawn alone \n" ); document.write( "then \n" ); document.write( "w-5 = time it takes Shelly to cut \n" ); document.write( ". \n" ); document.write( "2(1/w + 1/(w-5)) = 1 \n" ); document.write( "multiplying both sides by: w(w-5) \n" ); document.write( "2((w-5) + w) = w(w-5) \n" ); document.write( "2(2w-5) = w(w-5) \n" ); document.write( "4w-10 = w^2-5w \n" ); document.write( "-10 = w^2-9w \n" ); document.write( "0 = w^2-9w+10 \n" ); document.write( "Apply the quadratic formula to yield: \n" ); document.write( "w = {7.7, 1.3} \n" ); document.write( "Throw out the 1.3 answer (extraneous) leaving us with: \n" ); document.write( "w = 7.7 hours \n" ); document.write( ". \n" ); document.write( "Details of quadratic formula to follow: \n" ); document.write( "
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