document.write( "Question 299622: at maximum speed, an airplane travels 2400 miles against the wind in 6 hours. Flying with the wind, the plane can travel the same distance in 5 hours.
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document.write( "what is the speed of the airplane with no wind? \n" );
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Algebra.Com's Answer #215245 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let speed of plane in still air bex\r \n" ); document.write( "\n" ); document.write( "and wind rate be y\r \n" ); document.write( "\n" ); document.write( "2400 / x-y = 6\r \n" ); document.write( "\n" ); document.write( "2400/6 = x-y\r \n" ); document.write( "\n" ); document.write( "400 = x-y\r \n" ); document.write( "\n" ); document.write( "2400 / x+y=5\r \n" ); document.write( "\n" ); document.write( "x+y = 480\r \n" ); document.write( "\n" ); document.write( "x-y+ x+y = 480+400\r \n" ); document.write( "\n" ); document.write( "2x=880\r \n" ); document.write( "\n" ); document.write( "x=440 mph rate of plane in still air\r \n" ); document.write( "\n" ); document.write( "so y= 40 mph rate of wind \n" ); document.write( " |