document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299584>Question 299584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "Find the perimeter and area of a right triangle if the shortest side is 12 in. and the longest side is 37 in. Include correct units with each part of your solution.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215243 by </B><A HREF=/tutors/aboutme.mpl?userid=dabanfield><B>dabanfield(803)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=dabanfield><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the perimeter and area of a right triangle if the shortest side is 12 in. and the longest side is 37 in. Include correct units with each part of your solution.\r<BR>\n" );
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document.write( "Let x be the third side. Then by the Pythagorean Theorem we have:\r<BR>\n" );
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document.write( "x^2 + 12^2 = 37^2<BR>\n" );
document.write( "x^2 + 144 = 1369<BR>\n" );
document.write( "x^2 = 1369-144<BR>\n" );
document.write( "x^2 = 1225<BR>\n" );
document.write( "x = 35\r<BR>\n" );
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document.write( "The perimeter Of the triangle is 12+35+37 = 84 \r<BR>\n" );
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document.write( "The area, using the formula Area = (base*height)/2, is:\r<BR>\n" );
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document.write( "(35*12)/2 = 210\r<BR>\n" );
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