document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299584>Question 299584</A>: <I><SPAN STYLE=\"word-break: break-all;\"> <BR>\n" );
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document.write( "Find the perimeter and area of a right triangle if the shortest side is 12 in. and the longest side is 37 in. Include correct units with each part of your solution.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215242 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215242\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> since it is right triangle apply pythagoras rheorem\r<BR>\n" );
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document.write( "hyp^2-side1^2  = side2^2\r<BR>\n" );
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document.write( "37^2-12^=side2^2\r<BR>\n" );
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document.write( "sqrt(37^2-12^2) = side2\r<BR>\n" );
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document.write( "35 = side2\r<BR>\n" );
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document.write( "side1 = 12 inches\r<BR>\n" );
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document.write( "side2 = 35 inches\r<BR>\n" );
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document.write( "hypotenuse = 37 inches\r<BR>\n" );
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document.write( "perimeter = 84 inches\r<BR>\n" );
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document.write( "area of right triangle = 1/2 * side1 * side2\r<BR>\n" );
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document.write( "A= 1/2 *12*35\r<BR>\n" );
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document.write( "A= 210 square inches\r<BR>\n" );
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