document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=35452>Question 35452</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The swinomish planning office has 300 feet of fencing and wants to enclose a rectangular area of 3600 square feet to protect a cultural site.  What should the length and width of the fenced area be. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #21523 by </B><A HREF=/tutors/aboutme.mpl?userid=rapaljer><B>rapaljer(4671)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rapaljer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rapaljer><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=21523\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x = width of the rectangle<BR>\n" );
document.write( "y = length of the rectangle\r<BR>\n" );
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document.write( "Two equations are given in this problem:<BR>\n" );
document.write( "Area = xy = 3600 square feet<BR>\n" );
document.write( "Perimeter = 2x+2y = 300 feet\r<BR>\n" );
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document.write( "In the second equation, it will be easy to solve for y by dividing both sides by 2:<BR>\n" );
document.write( "x+y = 150\r<BR>\n" );
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document.write( "y= 150-x\r<BR>\n" );
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document.write( "Substitute this back into the first equation:\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=xy+=+3600 ALIGN=MIDDLE  ALT=\"xy+=+3600\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=x%28150-x%29+=+3600 ALIGN=MIDDLE  ALT=\"x%28150-x%29+=+3600\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=150x+-+x%5E2+=+3600 ALIGN=MIDDLE  ALT=\"150x+-+x%5E2+=+3600\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "This is a quadratic equation.  Set the equation equal to zero, by adding <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%2Bx%5E2+-150x ALIGN=MIDDLE  ALT=\"%2Bx%5E2+-150x\"   DISABLED_style= \"max-width:90%; height:auto;\" > to each side of the equation.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0+=+x%5E2+-+150x+%2B3600 ALIGN=MIDDLE  ALT=\"0+=+x%5E2+-+150x+%2B3600\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Does it factor???  Probably so!<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0=%28x-30%29%28x-90%29 ALIGN=MIDDLE  ALT=\"0=%28x-30%29%28x-90%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "x=30 or x= 120\r<BR>\n" );
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document.write( "If x = 30, then y = 120, and if x= 120, then y = 30.  It would be appropriate to say that the width would be the smaller number x= 30 feet, and the length is the larger number, which would be y = 120 feet.\r<BR>\n" );
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document.write( "R^2 at SCC </SPAN>\n" );
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