document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299434>Question 299434</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A woman can ride a bicycle 25 miles in the same time that it takes her to walk 5 miles. if she can ride 8 mph faster than she walk, how fast can she walk? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215148 by </B><A HREF=/tutors/aboutme.mpl?userid=Greenfinch><B>Greenfinch(383)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Greenfinch><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Greenfinch><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let her walk at X mph, She therefore cycles at X + 8 mph<BR>\n" );
document.write( "so 25/(X + 8) = 5/X<BR>\n" );
document.write( "25X = 5X + 40<BR>\n" );
document.write( "20X = 40<BR>\n" );
document.write( "X = 2, so she walks at 2 mph and cycles at 10 mph<BR>\n" );
document.write( "Check - 25 miles at 10 mph takes 2.5 hours<BR>\n" );
document.write( "walking 5 miles at 2 mph also takes 2.5 hours </SPAN>\n" );
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