document.write( "Question 299373: reverse foil or grouping
\n" ); document.write( "2x^2+15x+25
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Algebra.Com's Answer #215143 by jim_thompson5910(35256)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "Looking at the expression \"2x%5E2%2B15x%2B25\", we can see that the first coefficient is \"2\", the second coefficient is \"15\", and the last term is \"25\".\r
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\n" ); document.write( "\n" ); document.write( "Now multiply the first coefficient \"2\" by the last term \"25\" to get \"%282%29%2825%29=50\".\r
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\n" ); document.write( "\n" ); document.write( "Now the question is: what two whole numbers multiply to \"50\" (the previous product) and add to the second coefficient \"15\"?\r
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\n" ); document.write( "\n" ); document.write( "To find these two numbers, we need to list all of the factors of \"50\" (the previous product).\r
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\n" ); document.write( "\n" ); document.write( "Factors of \"50\":\r
\n" ); document.write( "\n" ); document.write( "1,2,5,10,25,50\r
\n" ); document.write( "\n" ); document.write( "-1,-2,-5,-10,-25,-50\r
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\n" ); document.write( "\n" ); document.write( "Note: list the negative of each factor. This will allow us to find all possible combinations.\r
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\n" ); document.write( "\n" ); document.write( "These factors pair up and multiply to \"50\".\r
\n" ); document.write( "\n" ); document.write( "1*50 = 50
\n" ); document.write( "2*25 = 50
\n" ); document.write( "5*10 = 50
\n" ); document.write( "(-1)*(-50) = 50
\n" ); document.write( "(-2)*(-25) = 50
\n" ); document.write( "(-5)*(-10) = 50\r
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\n" ); document.write( "\n" ); document.write( "Now let's add up each pair of factors to see if one pair adds to the middle coefficient \"15\":\r
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First NumberSecond NumberSum
1501+50=51
2252+25=27
5105+10=15
-1-50-1+(-50)=-51
-2-25-2+(-25)=-27
-5-10-5+(-10)=-15
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\n" ); document.write( "\n" ); document.write( "From the table, we can see that the two numbers \"5\" and \"10\" add to \"15\" (the middle coefficient).\r
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\n" ); document.write( "\n" ); document.write( "So the two numbers \"5\" and \"10\" both multiply to \"50\" and add to \"15\"\r
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\n" ); document.write( "\n" ); document.write( "Now replace the middle term \"15x\" with \"5x%2B10x\". Remember, \"5\" and \"10\" add to \"15\". So this shows us that \"5x%2B10x=15x\".\r
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\n" ); document.write( "\n" ); document.write( "\"2x%5E2%2Bhighlight%285x%2B10x%29%2B25\" Replace the second term \"15x\" with \"5x%2B10x\".\r
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\n" ); document.write( "\n" ); document.write( "\"%282x%5E2%2B5x%29%2B%2810x%2B25%29\" Group the terms into two pairs.\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%2B5%29%2B%2810x%2B25%29\" Factor out the GCF \"x\" from the first group.\r
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\n" ); document.write( "\n" ); document.write( "\"x%282x%2B5%29%2B5%282x%2B5%29\" Factor out \"5\" from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x%2B5%29%282x%2B5%29\" Combine like terms. Or factor out the common term \"2x%2B5\"\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So \"2x%5E2%2B15x%2B25\" factors to \"%28x%2B5%29%282x%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "In other words, \"2x%5E2%2B15x%2B25=%28x%2B5%29%282x%2B5%29\".\r
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\n" ); document.write( "\n" ); document.write( "Note: you can check the answer by expanding \"%28x%2B5%29%282x%2B5%29\" to get \"2x%5E2%2B15x%2B25\" or by graphing the original expression and the answer (the two graphs should be identical).
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