document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299262>Question 299262</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given log10 2=.3010 and log10 3=.4771, find each logarithm without using a calculator.\r<BR>\n" );
document.write( "\n" );
document.write( "log10 20/27 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215104 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215104\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given log10 2=.3010 and log10 3=.4771, find each logarithm without using a calculator.<BR>\n" );
document.write( "log10 20/27<BR>\n" );
document.write( ".<BR>\n" );
document.write( "log10(20) - log10(27)<BR>\n" );
document.write( "log10(2*10) - log10(3^3)<BR>\n" );
document.write( "log10(2)+log10(10) - 3log10(3)<BR>\n" );
document.write( "log10(2)+1 - 3log10(3)<BR>\n" );
document.write( "Substitute in what was given:<BR>\n" );
document.write( ".3010 + 1 - 3(.4771)<BR>\n" );
document.write( "-0.1303 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );