document.write( "Question 299225: You invested $8000 in two accounts paying 3% and 8% annual interest, respectively. If the total interest earned for the year was $490, how much was invested at each rate? \n" ); document.write( "
Algebra.Com's Answer #215086 by mananth(16946)![]() ![]() You can put this solution on YOUR website! let the amount invested at 3% be x\r \n" ); document.write( "\n" ); document.write( "the amount invested at 8% will be 8000-x\r \n" ); document.write( "\n" ); document.write( "0.03x+0.08(8000-x)=490\r \n" ); document.write( "\n" ); document.write( "0.03x + 640 - 0.08x=490\r \n" ); document.write( "\n" ); document.write( "-0.05x= -150\r \n" ); document.write( "\n" ); document.write( "x= -150 / -0.05\r \n" ); document.write( "\n" ); document.write( "x=3000 which is amount invested at 3%\r \n" ); document.write( "\n" ); document.write( "Balance $5000 at *% \n" ); document.write( " |