document.write( "Question 299184: Solve and Verify:\r
\n" ); document.write( "\n" ); document.write( " $\"+log%282%2C%282-2x%29%29%2Blog%282%2C%281-x%29%29=5+\"$ \n" ); document.write( "

Algebra.Com's Answer #215084 by nerdybill(7384) $\"\"$ $\"About$

You can put this solution on YOUR website!
$\"+log%282%2C%282-2x%29%29%2Blog%282%2C%281-x%29%29=5+\"$
\n" ); document.write( " $\"+log%282%2C%282-2x%29%281-x%29%29=5+\"$
\n" ); document.write( " $\"+%282-2x%29%281-x%29=2%5E5+\"$
\n" ); document.write( " $\"+2-2x-2x%2B2x%5E2=32+\"$
\n" ); document.write( " $\"+2x%5E2-4x%2B2=32+\"$
\n" ); document.write( " $\"+x%5E2-2x%2B1=16+\"$
\n" ); document.write( " $\"+x%5E2-2x-15=0\"$
\n" ); document.write( " $\"+%28x%2B3%29%28x-5%29=0+\"$
\n" ); document.write( ".
\n" ); document.write( "x = {-2, 5}
\n" ); document.write( "Toss out 5 as a solution, it's an extraneous solution leaving (causes problems with the original equation). Therefore, the solution:
\n" ); document.write( "x = -2 \n" ); document.write( "

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