document.write( "Question 299158: Solve by the LCM method:\r
\n" ); document.write( "\n" ); document.write( "\"6%2F%28y%2B3%29%2B+2%2Fy+=%285y-3%29%2F%28y%5E2-9%29\"\r
\n" ); document.write( "\n" ); document.write( "I am unable to come up with the LCD: (y+3)(y-3)? Unsure of how to work this. Once I have the LCD, I believe I will be able to solve it. Thank you in advance for your help.
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Algebra.Com's Answer #215072 by mananth(16946)\"\" \"About 
You can put this solution on YOUR website!
\"6%2F%28y%2B3%29%2B+2%2Fy+=%285y-3%29%2F%28y%5E2-9%29\"\r
\n" ); document.write( "\n" ); document.write( "6 / y+3 -5y-3 / y^2-9= 2/y\r
\n" ); document.write( "\n" ); document.write( "6(y-3) - (5y-3) / y^2-9 = 2/y\r
\n" ); document.write( "\n" ); document.write( "6y-18 -5y+15 = 2(y^2-9) /y\r
\n" ); document.write( "\n" ); document.write( "y-3= 2(y^2-9) /y\r
\n" ); document.write( "\n" ); document.write( "y(y-3)= 2 (y^2-9)\r
\n" ); document.write( "\n" ); document.write( "y= 2(y+3)(y-3) / (y-3)\r
\n" ); document.write( "\n" ); document.write( "y=2(y+3)\r
\n" ); document.write( "\n" ); document.write( "y=2y+6\r
\n" ); document.write( "\n" ); document.write( "y=-6\r
\n" ); document.write( "\n" ); document.write( "Ananth
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