document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299196>Question 299196</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution.\r<BR>\n" );
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document.write( "A sum of money amounting to $3.80 consists of dimes and quarters. If there are 20 coins in all, how many are quarters? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215069 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215069\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the number of dimes be x<BR>\n" );
document.write( "the number of quarters be y\r<BR>\n" );
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document.write( "x+y =20 \r<BR>\n" );
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document.write( "10x+25y=380 cents\r<BR>\n" );
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document.write( "10x+10y -(10x+25y)=200 -380\r<BR>\n" );
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document.write( "10x+10y-10x -25y=-180\r<BR>\n" );
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document.write( "-15y= -180\r<BR>\n" );
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document.write( "y=-180/-15\r<BR>\n" );
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document.write( "y=12 the number of quarters\r<BR>\n" );
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document.write( "20-12 = 8 will be the number of dimes\r<BR>\n" );
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document.write( " </SPAN>\n" );
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