document.write( "Question 35368This question is from textbook
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document.write( ": The population of a city is given by P=5000e^kt where t is time in years, with t=0 coresponding in year to 2000. In 1990 the population was 34,500. Find the value of k and predict the population in 2030.
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document.write( "I come up with 123,608 if I use the negative in my problem
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document.write( "34,500 =5000e^k(-10)
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document.write( "6.9 = e^k(-10)
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document.write( "ln6.9 = k(-10)
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document.write( "P= 5000e^(-.193152141)(30)
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document.write( "P= 123,608 population in 2030
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document.write( "Is this correct??? Thinking it should be higher \n" );
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Algebra.Com's Answer #21505 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! The population of a city is given by P=5000e^kt where t is time in years, with t=0 coresponding in year to 2000. In 1990 the population was 34,500. Find the value of k and predict the population in 2030. \n" ); document.write( "I come up with 123,608 if I use the negative in my problem \n" ); document.write( "34,500 =5000e^k(-10) \n" ); document.write( "6.9 = e^k(-10) \n" ); document.write( "ln6.9 = k(-10) \n" ); document.write( "P= 5000e^(-.193152141)(30) \n" ); document.write( "P= 123,608 population in 2030 \n" ); document.write( "Is this correct??? Thinking it should be higher\r \n" ); document.write( "\n" ); document.write( "I think it is smaller than that. \n" ); document.write( "In 1990 the population was 34,500 \n" ); document.write( "In 2000 the population was only 5000 \n" ); document.write( "This is a decreasing population. \n" ); document.write( "The negative is correct but your exponent is not; you need to include \n" ); document.write( "the \"30\" in the exponent. \n" ); document.write( "Try P = 5000e^(-0.193152141*30)= 15 people. \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |