document.write( "Question 35368This question is from textbook
\n" ); document.write( ": The population of a city is given by P=5000e^kt where t is time in years, with t=0 coresponding in year to 2000. In 1990 the population was 34,500. Find the value of k and predict the population in 2030.
\n" ); document.write( "I come up with 123,608 if I use the negative in my problem
\n" ); document.write( "34,500 =5000e^k(-10)
\n" ); document.write( "6.9 = e^k(-10)
\n" ); document.write( "ln6.9 = k(-10)
\n" ); document.write( "P= 5000e^(-.193152141)(30)
\n" ); document.write( "P= 123,608 population in 2030
\n" ); document.write( "Is this correct??? Thinking it should be higher
\n" ); document.write( "

Algebra.Com's Answer #21505 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
The population of a city is given by P=5000e^kt where t is time in years, with t=0 coresponding in year to 2000. In 1990 the population was 34,500. Find the value of k and predict the population in 2030.
\n" ); document.write( "I come up with 123,608 if I use the negative in my problem
\n" ); document.write( "34,500 =5000e^k(-10)
\n" ); document.write( "6.9 = e^k(-10)
\n" ); document.write( "ln6.9 = k(-10)
\n" ); document.write( "P= 5000e^(-.193152141)(30)
\n" ); document.write( "P= 123,608 population in 2030
\n" ); document.write( "Is this correct??? Thinking it should be higher\r
\n" ); document.write( "\n" ); document.write( "I think it is smaller than that.
\n" ); document.write( "In 1990 the population was 34,500
\n" ); document.write( "In 2000 the population was only 5000
\n" ); document.write( "This is a decreasing population.
\n" ); document.write( "The negative is correct but your exponent is not; you need to include
\n" ); document.write( "the \"30\" in the exponent.
\n" ); document.write( "Try P = 5000e^(-0.193152141*30)= 15 people.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "
\n" );