document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=299082>Question 299082</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!<BR>\n" );
document.write( "Hoping you can help! Working on Advanced Algebra....notes aren't helping and I can't remember how to do these problems.\r<BR>\n" );
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document.write( "log3 9 + log3 27<BR>\n" );
document.write( "instructions are to  Express as a single logarithm and simplify if possible!<BR>\n" );
document.write( "thank you!!!!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #215022 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=215022\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> log3 9 + log3 27<BR>\n" );
document.write( "Adding the logs same as multiplying<BR>\n" );
document.write( "log3(9*27) = log3(243); a single logarithm<BR>\n" );
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document.write( "Exponent equiv of logs<BR>\n" );
document.write( "log3(243) = y<BR>\n" );
document.write( "3^y - 243<BR>\n" );
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document.write( "What power of 3 is 243<BR>\n" );
document.write( "y = 5<BR>\n" );
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document.write( "therefore<BR>\n" );
document.write( "log3(243) = 5<BR>\n" );
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