document.write( "Question 298906: Translate the problem into a pair of linear equations in two variables. Solve the equations using either elimination or substitution. State your answer for the specified variable.\r
\n" ); document.write( "\n" ); document.write( "A merchant has coffee worth $3 a pound that she wishes to mix with 6 pounds of coffee worth $8 a pound to get a mixture that can be sold for $4 a pound. How many pounds of the $3 coffee should be used? \n" ); document.write( "
Algebra.Com's Answer #215004 by ankor@dixie-net.com(22740)\"\" \"About 
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A merchant has coffee worth $3 a pound that she wishes to mix with 6 pounds of
\n" ); document.write( " coffee worth $8 a pound to get a mixture that can be sold for $4 a pound.
\n" ); document.write( " How many pounds of the $3 coffee should be used?
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\n" ); document.write( "It does not make sense to use two variables in this problem
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\n" ); document.write( "Let x = amt of $3 coffee:
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\n" ); document.write( "A mixture equation
\n" ); document.write( "3x + 8(6) = 4(x+6)
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\n" ); document.write( "3x + 48 = 4x + 24
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\n" ); document.write( "48 - 24 = 4x - 3x
\n" ); document.write( "24 = x
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\n" ); document.write( "24 lb of $3 coffee required to make 30 lb of $4 coffee \n" ); document.write( "
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