document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=298986>Question 298986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In the United States, one farmworker supplied agricultural products for an average of 106 people.  Assume the standard deviation is 16.1.  If 35 farmworkers are selected, find the probability that the mean number of people supplied is between 100 and 110. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #214983 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=214983\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> In the United States, one farmworker supplied agricultural products for an average of 106 people. Assume the standard deviation is 16.1. If 35 farmworkers are selected, find the probability that the mean number of people supplied is between 100 and 110.<BR>\n" );
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document.write( "t(100) = (100-106)/[16.1/sqrt(35)] = -2.2048<BR>\n" );
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document.write( "t(110) = (110-106)/[16.1/sqrt(35)] = 1.4698<BR>\n" );
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document.write( "P(100<= x-bar <=110) = P(-2.2048<= t <= 1.4698 with df=34)<BR>\n" );
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document.write( "= tcdf(-2.2048,1.4698,34)<BR>\n" );
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document.write( "= 0.9074<BR>\n" );
document.write( "=================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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