document.write( "Question 298862: By cutting away identical squares from each corner of a rectangular piece of cardboard and folding up the resulting flaps, an open box may be made.
\n" ); document.write( "(a) If the cardboard is 15 in. long and 7 in. wide, find the dimensions of the box that will yield the maximum volume.
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Algebra.Com's Answer #214945 by Earlsdon(6294)\"\" \"About 
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First write the equation for the volume of the box.
\n" ); document.write( "If you cut squares from each corner where the side of the square is x inches, then the volume of the resulting box when the flaps are folded up can be expressed as:
\n" ); document.write( "\"V+=+%2815-2x%29%287-2x%29X\" which simplifies to:
\n" ); document.write( "\"V+=+4x%5E3-44x%5E2%2B105x\" To find the value of x which yields the maximum of volume (V), take the first derivative of this equation and set it equal to zero.
\n" ); document.write( "\"dV%2Fdx+=+12x%5E2-88x%2B105\" Set this equal to zero and solve for x;
\n" ); document.write( "\"12x%5E2-88x%2B105+=+0\" Solve by the quadratic formula:\"x+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F2a\" where a = 12, b = -88, and c = 105. You can do this and you should get:
\n" ); document.write( "\"x+=+5.833\" or \"x+=+1.5\"
\n" ); document.write( "Discard \"x+=+5.833\" because it would result in a negative value for the length of the bottom of the box: \"7-2x+=+7-11.66\"=\"-4.66\", so...
\n" ); document.write( "\"x+=+1.5\"inches.
\n" ); document.write( "The dimensions of the box are:
\n" ); document.write( "Length, \"L+=+15-2x\"=\"15-2%281.5%29+=+15-3\"=\"12\"inches.
\n" ); document.write( "Width, \"W+=+7-2x\"+\"7-2%281.5%29+=+7-3\"=\"4\"inches.
\n" ); document.write( "Height, \"h+=+x\"=\"1.5\"inches.
\n" ); document.write( "The maximum volume of the box would be:
\n" ); document.write( "\"V%5Bmax%5D+=+L%2AW%2Ah\"
\n" ); document.write( "\"V%5Bmax%5D+=+12%2A4%2A1.5\"
\n" ); document.write( "\"V%5Bmax%5D+=+72\"cubic inches.
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