document.write( "Question 298907: The speed of a passenger train is 10mph faster than the speed of a freight train. The passenger train travels 290 miles in the same time it takes the freight train to travel 240 miles. Find the speed of each train. A) Passenger train_? B) Freight train_ (mph)? \n" ); document.write( "

Algebra.Com's Answer #214936 by J.A.Romero(2) $\"\"$ $\"About$

You can put this solution on YOUR website!
freighttrain= $\"r\"$ :(mph)
\n" ); document.write( "passengertrain= $\"r%2B10\"$ :(mph)
\n" ); document.write( "distance=rate*time, $\"D=RT\"$
\n" ); document.write( "passengertrain= $\"290miles=%28dist%2Ft%29%2B10%2At\"$
\n" ); document.write( "d=rt; $\"290=R%2B10%2AT\"$ ; $\"T=290%2FR%2B10\"$
\n" ); document.write( "freighttrain= $\"240miles=%28dist%2Ft%29%28t%29\"$
\n" ); document.write( "d=rt; $\"240=R%2AT\"$ ; $\"T=240%2FR\"$
\n" ); document.write( " $\"290%2Fr%2B10=240%2Fr\"$
\n" ); document.write( " $\"r%28r%2B10%29%2A240%2Fr=r%28r%2B10%29%2A290%2Fr%2B10\"$
\n" ); document.write( " $\"%28r%2B10%29%2A240=290%28r%29\"$
\n" ); document.write( " $\"240r%2B2%2C400=290r\"$
\n" ); document.write( " $\"240r%2B2%2C400-240r=290r-240r\"$ ; $\"2%2C400=50r\"$
\n" ); document.write( "freighttrain= $\"r\"$ :(mph)
\n" ); document.write( "passengertrain= $\"r%2B10\"$ :(mph)
\n" ); document.write( " $\"R=48\"$
\n" ); document.write( " $\"R=48%2B10\"$
\n" ); document.write( "Freighttrain= $\"48%3A%28mph%29\"$
\n" ); document.write( "Passengertrain= $\"58%3A%28mph%29\"$ \n" ); document.write( "

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