document.write( "Question 298907: The speed of a passenger train is 10mph faster than the speed of a freight train. The passenger train travels 290 miles in the same time it takes the freight train to travel 240 miles. Find the speed of each train. A) Passenger train_? B) Freight train_ (mph)? \n" ); document.write( "
Algebra.Com's Answer #214933 by checkley77(12844)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "290=(R+10)T PASSENGER TRAIN \n" ); document.write( "T=290/(R+10) \n" ); document.write( "240=RT FREIGHT TRAIN \n" ); document.write( "T=240/R \n" ); document.write( "290/(R+10)=240/R \n" ); document.write( "290R=240(R+10) \n" ); document.write( "290R=240R+2400 \n" ); document.write( "290R-240R=2400 \n" ); document.write( "50R=2400 \n" ); document.write( "R=2400/50 \n" ); document.write( "R=48 MPH FOR THE FREIGHT TRAIN. \n" ); document.write( "48+10=58 MPH FOR THE PASSENGER TRAIN. \n" ); document.write( "240=48T \n" ); document.write( "T=240/48 \n" ); document.write( "T=5 HOURS IS THE TIME OF THE TRIP. \n" ); document.write( "PROOF: \n" ); document.write( "290=58*5 \n" ); document.write( "290=290 \n" ); document.write( " \n" ); document.write( " |