document.write( "Question 298073: Hey I've tried this 3 times and I keep getting stuck halfway through it. Could someone please take me through the steps.\r
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document.write( "z = f(x,y) of x and y, which has partial derivatives: dz/dx = 2xy and dz/dy = x^2\r
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document.write( "given the relations: r = sqrt(x^2+y^2) and theta = arctan (y/2)
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document.write( "x = r cos (theta) and y = r sin (theta)\r
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document.write( "find dz/d(theta) (expressed in terms of r and theta) \n" );
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Algebra.Com's Answer #214866 by user_dude2008(1862)![]() ![]() ![]() You can put this solution on YOUR website! dz/dx = 2xy \n" ); document.write( "z=x^2y+C\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "dz/dy = x^2 \n" ); document.write( "z=x^2y+C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z = f(x,y) = x^2y+C\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z=x^2y+C\r \n" ); document.write( "\n" ); document.write( "z=(r*cos(theta))^2*r*sin(theta)+C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z=r^2*cos^2(theta)*r*sin(theta)+C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "z=r^3*cos^2(theta)*sin(theta)+C\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "dz/d(theta) = r^3[-2cos(theta)sin^2(theta)+cos^3(theta)]\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |